Jesus' question at Yahoo Answers regarding finding total cost function

  • #1
MarkFL
Gold Member
MHB
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Here is the question:

Function Math Question?

I am having a problem solving this question, any help is appreciated!

An oil refinery is located on the north bank of a straight river that is 2 km wide. A pipeline is to be constructed from the refinery to a point P on the south bank of the river, and then along the river to storage tanks on the south side of the river 6 km east of the refinery. The cost of laying pipe is $400,000 per km over land, and $800,000 per km under the river. Express the total cost of the pipeline as a function of the distance from P to the storage tanks.

I have posted a link there to this topic so the OP can see my work.
 
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  • #2
Hello Jesus,

I would first label some variables:

\(\displaystyle L_R\) = the length of the pipeline under the river.

\(\displaystyle L_L\) = the length of the pipeline over land. This is the variable with which we are to express the total cost function.

\(\displaystyle D\) = the distance downriver the tanks are from the refinery.

\(\displaystyle W\) = the width of the river.

\(\displaystyle C_R\) = cost in dollars per unit length to lay pipe under the river.

\(\displaystyle C_L\) = cost in dollars per unit length to lay pipe over the land.

Next, let's draw a diagram:

View attachment 1022

$R$ is the location of the refinery, and $T$ is the location of the tanks.

We see that by Pythagoras, we have:

\(\displaystyle L_R=\sqrt{\left(D-L_L \right)^2+W^2}\)

Now, the total cost is given by:

\(\displaystyle C=C_RL_R+C_LL_L\)

Substituting for $L_R$, we have:

\(\displaystyle C\left(L_L \right)=C_R\sqrt{\left(D-L_L \right)^2+W^2}+C_LL_L\)

Using the given data for the parameters:

\(\displaystyle C_R=800000,\,D=6,\,W=2,\,C_L=400000\)

we have:

\(\displaystyle C\left(L_L \right)=800000\sqrt{\left(6-L_L \right)^2+2^2}+400000L_L\)

Factoring and simplifying, we have:

\(\displaystyle C\left(L_L \right)=400000\left(2\sqrt{L_L^2-12L_L+40}+L_L \right)\)
 

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