Joint probability distribution

  • Thread starter Gauss M.D.
  • Start date
  • #1
153
1

Homework Statement



f(x,y) = x2 + xy3 for 0 < x < 1, 0 < y < 2
and 0 otherwise.

Calculate P(X+Y < 1)

Homework Equations





The Attempt at a Solution



P(X+Y < 1) = P(X < 1-Y) which means y is now bounded by 0:1 instead of 0:2 and x is bounded by 0:y.

So we get ∫[0-1][0-y] x2 + xy3 dx dy

Integrating twice I get the answer P(X < 1-Y) = 1/8, which is incorrect.

What am I doing wrong?
 

Answers and Replies

  • #3
153
1
I.e. nevermind.
 

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