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Joint probability distribution

  1. Apr 25, 2013 #1
    1. The problem statement, all variables and given/known data

    f(x,y) = x2 + xy3 for 0 < x < 1, 0 < y < 2
    and 0 otherwise.

    Calculate P(X+Y < 1)

    2. Relevant equations



    3. The attempt at a solution

    P(X+Y < 1) = P(X < 1-Y) which means y is now bounded by 0:1 instead of 0:2 and x is bounded by 0:y.

    So we get ∫[0-1][0-y] x2 + xy3 dx dy

    Integrating twice I get the answer P(X < 1-Y) = 1/8, which is incorrect.

    What am I doing wrong?
     
  2. jcsd
  3. Apr 25, 2013 #2
  4. Apr 25, 2013 #3
    I.e. nevermind.
     
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