Just needed to be proofread (easy forumula)

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The discussion revolves around calculating the work output, work input, and efficiency of a screw pump based on given parameters. The work output is calculated as 2600J, derived from lifting 130 liters of water (1300N) to a height of 2m. The work input is determined to be 5300J, calculated from the force applied and the distance traveled by the handle. The efficiency of the pump is then found to be 49%, calculated by dividing work output by work input. The calculations presented appear to be correct.
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Homework Statement


A screw pump is turned with a force of 125N. The handle traces a circle with a DIAMETER of 30cm, and is turned 45 times. The pump lifts 130 litres of water 2m high. (1 litre of water = 1kg aka 10N)
What is the work output?
What is the work input?
What is the efficiency of the pump?



Homework Equations





The Attempt at a Solution


For work output, i did: 130 times 10 = 1300N times 2M = 2600J
Work output: 2600J

For work input, i did Pi times .30m = .94m times 45 = 42.4M times 125N = 5300J
Work input: 5300J

Effiiciency: 2600J divided by 5300J = 49%


Is this correct?
 
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