JWST Sensor Thread - Split

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  • Thread starter Devin-M
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Devin-M
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Sorry I was responding to this comment:
You can assume though that if the sensor was actually placed in a passive circuit, such that the photodetector, other components in the circuit, its enclosure, and everything else in the vicinity is all at the same temperature, the dark current density would measure 0.
I was wondering what powers the dark current measured in the paper when there is zero bias voltage, in the dark, and the sensor and surroundings at the same temperature? From Ohm's law we have P=I^2R
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