Devin-M
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I calculated the surface area for one of the JWST sensors is approximately 12.9cm^2.DrDu said:You are loosing also 50% more of the photons emitted by the sensor which otherwise would have been reflected back onto the sensor or onto some part in thermal equilibrium with the detector.
http://www.teledyne-si.com/products/Documents/TSI-0855 H2RG Brochure-25Feb2022.pdf
I used the Planck radiation formula for a 300k black body, 0.95 emissivity, 12.9cm^2 and a radiation wavelength range from 3400nm to 3600nm and get 0.00019W of radiated power for that wavelength range which is 0.034% of the total radiated power.
http://hyperphysics.phy-astr.gsu.edu/hbase/quantum/radfrac.html
I calculated the spectral responsivity of a 300k HgCdTe panel from figure 12 in this paper is 0.0003 amps from 0.00019W of 3.5 micron light.
https://www.researchgate.net/profile/Pawel-Madejczyk-2/publication/343856156_Higher_Operating_Temperature_IR_Detectors_of_the_MOCVD_Grown_HgCdTe_Heterostructures/links/6086b5a62fb9097c0c0d3442/Higher-Operating-Temperature-IR-Detectors-of-the-MOCVD-Grown-HgCdTe-Heterostructures.pdf?origin=publication_detail
I found the typical reverse leakage current of a particular Schottky diode is 0.00000065 amps with 5 reverse volts at 298K from this datasheet:
https://www.st.com/resource/en/datasheet/bat20j.pdf
When I subtract the max expected 0.00000065 amps reverse current through the Schottky diode from the 0.0003 amps forward current into the capacitor from the spectral responsivity of the HgCdTe panel from the 0.00019W of 3.5 micron photons from the 12.9cm^2 300k black body in close proximity of the 300k 12.9cm^2 HgCdTe photovoltaic panel, I calculate a net current into the capacitor of 0.00029 amps.
I assume this is a mistake since the Carnot efficiency for the setup is 0%. On which step did I mess up the calculations?
Circuit diagram for reference: