Kinematcis, archer and his arrow

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SUMMARY

An archer shoots an arrow vertically with an initial velocity of 45 m/s. To calculate the maximum height, the kinematic equation Vf^2 = Vo^2 + 2as is utilized, where Vf is the final velocity (0 m/s at the peak), Vo is the initial velocity (45 m/s), a is the acceleration due to gravity (-9.8 m/s²), and s is the displacement (maximum height). By rearranging the equation and substituting the known values, the maximum height is determined to be 103.32 meters, confirming the calculation's accuracy.

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alicia113
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An archer shoots an arrow straight up into the air with an initial velocity of 45 m/s . Calculate the maximum height of the arrow.

The equation I would use for this is:
Vf^2 = Vo^2+2as

where:
Vf is final velocity
Vo is initial velocity
a is acceleration (gravity)
s is displacement

plug in the numbers we know:
0^2 = 45^2 + 2(-9.8)s

now solve for s

0=2025-19.6s
-2025=-19.6s

s = 103.32 meters.is this right
 
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Yes.
I would say it is best to rearrange the equation to make s the subject first and then substitute numbers.
 

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