Kinematics 4 -- Calculate the velocity from the position versus time graph

Click For Summary

Homework Help Overview

The discussion revolves around calculating velocity from a position versus time graph, specifically focusing on average and instantaneous velocities. Participants explore various methods to interpret the graph and derive velocities based on given time intervals.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of graphical methods to determine average velocity and question the relationship between average and instantaneous velocity. Some suggest numerical methods for solving the problem, while others propose visual interpretation of the graph.

Discussion Status

The discussion is active, with participants sharing insights and clarifying concepts. Some guidance has been provided regarding the interpretation of average velocity as the slope of a line, and there is acknowledgment of specific time moments relevant to the problem.

Contextual Notes

There are references to specific parts of the problem and the use of standard methods, such as interpolation techniques, which may indicate constraints or specific requirements in the homework assignment.

Pushoam
Messages
961
Reaction score
53

Homework Statement


upload_2017-7-11_21-51-59.png


Homework Equations


vav = total distance traveled/ total time taken

The Attempt at a Solution


I have a problem in part c .
How am I supposed to solve it?
Is there any standard way to solve it?
 

Attachments

  • upload_2017-7-11_21-50-27.png
    upload_2017-7-11_21-50-27.png
    32.2 KB · Views: 612
Physics news on Phys.org
Take an arbitrary time to. How can you graphically determine the average velocity for the time interval between t = 0 and t = to? [Edit: Can you interpret the average velocity as the slope of some line?]

It might help to first take a specific example. Suppose you take t0 = 10 s. How would you get the average velocity for the time interval t = 0 to t = 10 s? Does this average velocity equal the instantaneous velocity at t = 10 s?
 
Last edited:
Pushoam said:
I have a problem in part c .
How am I supposed to solve it?
Is there any standard way to solve it?
Irodov?

Pushoam said:
Is there any standard way to solve it?
One standard way could be using numerical methods. Newton's forward interpolation or Lagrange's interpolation will work.
You can find the displacement-time relationship for three intervals: i)from t=0 to t=10s ii)from t=10 to t=14.5s iii) from t=14.5 to t=20s.
Once you have the s-t relationship, you can find t0.
 
As TSny indicates, you can pretty much determine the answer for part c by eye, just by looking at the graph.
 
TSny said:
Edit: Can you interpret the average velocity as the slope of some line?]
Thanks.
I got it.
I never interpreted average velocity as the slope of some line. Thanks for this insight.
So, what I have to find out is the time moment at which the line whose slope defines the instantaneous velocity passes through the origin. This time moment turns out to be 16 s.
cnh1995 said:
Irodov?

Yes

Thanks to all for replying.
 
  • Like
Likes   Reactions: cnh1995
Pushoam said:
So, what I have to find out is the time moment at which the line whose slope defines the instantaneous velocity passes through the origin. This time moment turns out to be 16 s.
Yes. Good work.
 
Thanks, TSny
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
Replies
40
Views
3K
  • · Replies 14 ·
Replies
14
Views
6K
Replies
1
Views
3K
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
9K
Replies
46
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K