Kinematics - Constant Deceleration

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SUMMARY

The discussion focuses on solving a kinematics problem involving constant deceleration of a car. The problem requires determining the reaction time and the magnitude of deceleration when a car stops from initial speeds of 50 mi/hr and 30 mi/hr over specified distances. Key equations from "Fundamentals of Physics" by Halliday, Resnick, and Walker are utilized, including the equations for displacement and acceleration. A critical insight is the necessity of consistent unit conversion to solve for unknown variables effectively.

PREREQUISITES
  • Understanding of kinematic equations, specifically for constant acceleration.
  • Familiarity with unit conversion between miles per hour and feet per second.
  • Basic knowledge of algebra to manipulate equations with multiple variables.
  • Concept of reaction time in the context of motion and braking.
NEXT STEPS
  • Study the derivation and application of kinematic equations for constant acceleration.
  • Learn about unit conversion techniques, particularly between different measurement systems.
  • Explore the concept of reaction time and its impact on stopping distances in vehicle dynamics.
  • Investigate real-world applications of kinematics in automotive safety and braking systems.
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in the principles of motion and braking dynamics in vehicles.

rtsphysics
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Homework Statement


To stop a car, you require first a certain reaction time to begin braking; then the car slows down under the constant braking deceleration. Suppose that the total distance moved by your car during these two phases is 186 ft when its initial speed is 50 mi/hr, and 80 ft when its initial speed is 30 mi/hr. What are (a) your reaction time and (b) the magnitude of the deceleration?

Problem taken from Fundamentals of Physics 5th ed. Halliday, Resnick, Walker Pg. 32, prob. 51P


Homework Equations



x - x0 = 0.5(v0 + v)t
x - x0 = vt - 0.5at2
v2 = v02 + 2a(x - x0)


The Attempt at a Solution


Ok so I tried plugging in the displacements 186 ft and 80 ft into the above equations. The acceleration is constant so I can use the equations above. However, when i plug it in, I always get two or more equations with at least two variables. For example, plugging both numbers in the first equation, we get:

186 ft = 0.5(50mi/hr + v1)t1
80 ft = 0.5(30mi/hr + v2)t2

I don't see how I can get one of the unknown variables such as final velocity using any other equations, such as v = v0 + at, since i don't know a or t...

Any help would be appreciated!
 
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you don't need an equation for the final velocity ,for it is given by statement of "to stop a car".
 
Try setting all your units equal to each other. Make sure you are not setting feet equal with miles and hours with seconds. Convert feet to miles or miles/hr to feet/hr. All units of time should be the same unit and all the units of distance should be the same.
 

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