LoveBoy
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When we apply this equation ?
v^2-u^2=kt^2/2m
v^2-u^2=kt^2/2m
The discussion centers on the application of the kinematics equation v² - u² = kt²/2m, which appears to be a combination of two established equations: x = x₀ + v₀t + (1/2)at² and v² = v₀² + 2aΔx. Participants express confusion regarding the validity and context of the first equation, indicating that it lacks clarity and proper derivation from the standard kinematic equations. The conversation emphasizes the importance of understanding the foundational kinematic equations for accurate application in physics problems.
PREREQUISITESStudents of physics, educators teaching kinematics, and anyone seeking to clarify the application of motion equations in problem-solving scenarios.
Not sure what that equation is supposed to be. It looks like a mash up of these two:LoveBoy said:When we apply this equation ?
v^2-u^2=kt^2/2m
Thanks !Doc Al said:Not sure what that equation is supposed to be. It looks like a mash up of these two:
##x = x_0 + v_0 t + (1/2) a t^2##
##v^2 = v_0^2 + 2 a \Delta x##