Kinematics - Find velocity of the car

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SUMMARY

The discussion focuses on calculating the velocity of car A when it meets car B, given specific initial conditions and equations of motion. Car A starts with an initial velocity of 0 m/s, while car B has an initial velocity of 26.67 m/s and a negative acceleration of -1/6 times the acceleration of car A. The final results indicate that the acceleration of car A is 3.59 m/s², the time taken for car A to reach car B is 7.08 seconds, and the distance traveled by car B is 188 meters.

PREREQUISITES
  • Understanding of kinematic equations, specifically X_A(t) and V_B equations.
  • Knowledge of acceleration and its relationship to velocity and time.
  • Ability to manipulate algebraic expressions to solve for unknowns.
  • Familiarity with the concept of relative motion in physics.
NEXT STEPS
  • Study the derivation and application of kinematic equations in one-dimensional motion.
  • Learn how to solve systems of equations involving multiple variables in physics problems.
  • Explore the concept of relative acceleration and its implications in motion analysis.
  • Practice similar problems involving two objects in motion to reinforce understanding of the concepts.
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Students studying physics, particularly those focusing on kinematics, as well as educators seeking to enhance their teaching methods in motion analysis.

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Homework Statement



Find velocity of car A when car A and car B meet
Find the distance from where car B started to where car B meets car A
Find the time it takes car A to reach car B

initial velocity of car A is 0
initial velocity of car B is 26.67 m/s
at t=5, acceleration of car B = -1/6 * acceleration of car A
velocity of car A=velocity of car B when they meet

Homework Equations




X_A(t)=X_A(0) + V_A(0)*t + .5*a_A*t^2
V_B=V_B(0) + a_B*t

The Attempt at a Solution



distance of car A equation becomes this...90=.5*a_A*t^2
velocity of car B becomes this...V_B=-26.67 - 1/6*a_A*t

I tried solving X_A equation for a_A and using it in V_B but no luck, I spent 3 days trying every which way I could think of to find the answer.

The answers in the back of the book are
Acceleration of car A=3.59 m/s^2
time=7.08 s
distance car B travels=188 m
 

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#1. Write down the time taken for A, using the least number of unknowns (use as much of the given data as possible).

#2. Write down the final speed of A in a similar manner. This is also the final speed of B.

#3. Independently, write down an expression for the final speed of B in terms of the time taken (B takes the same time as A; see #1).

#4. Use the relationship between the two accelerations and set the two expressions for the final speed of B equal to each other.
 

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