bugatti79
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OkAlephZero said:dw/dx is the slope of the beam, which is assumed to be small. So dw/dx is also the angle the beam has rotated, in radians.
I understand this.AlephZero said:The top picture (Euler beam theory) assumes that cross sections of the beam stay perpendicular to the neutral axis. So the angle between a cross section and the vertical is the same as the slope of the beam.
Ok, how does the ##z\frac{dw}{dx}## come about? Is this equivalent to Z times the cos of the angle?AlephZero said:The picture is (stupidly, IMHO) drawn with a "left handed" coordinate system (z and w positive downwards not upwards) which is where the minus signs come from.
ThanksAlephZero said:In the bottom picture (Timoshenko beam theory) plane sections of the beam do not stay perpendicular to the neutral axis, so there is an extra shear strain (measured by angle gamma) involved.
bugatti79 said:Ok, how does the ##z\frac{dw}{dx}## come about? Is this equivalent to Z times the cos of the angle?
bugatti79 said:What practical examples are there where one shouldn't use Euler-Bernouilli to track beam deflection etc.