Kinetic and static frictional forces

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SUMMARY

The discussion focuses on calculating the horizontal force required to initiate movement of a block with a mass of 755N, given the coefficients of static and kinetic friction at 0.800 and 0.600, respectively. The force needed to overcome static friction can be determined using the formula: F = μ_s * N, where μ_s is the coefficient of static friction and N is the normal force. In this case, the normal force equals the weight of the block, which is 755N, leading to a required force of 604N to start the box moving.

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  • Understanding of static and kinetic friction coefficients
  • Knowledge of Newton's laws of motion
  • Ability to calculate normal force from weight
  • Familiarity with basic physics formulas
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  • Study the implications of different coefficients of friction on motion
  • Learn how to calculate forces in various friction scenarios
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Leestyn
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static and frictional forces applied to a block. what is the horizontal force required to start the box from moving. known is kinetic friction - .600 and static friction .800 the block has a mass of 755N
 
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Leestyn said:
static and frictional forces applied to a block. what is the horizontal force required to start the box from moving. known is kinetic friction - .600 and static friction .800 the block has a mass of 755N

Welcome to PF.

How is the coefficient of friction related to the weight?
 

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