1. The problem statement, all variables and given/known data Two blocks, of masses M = 2.0 kg and 2M are connected to a spring of spring constant k = 200 N/m that has one end fixed, as shown in the figure below. The horizontal surface and the pulley are frictionless, and the pulley has a moment of inertia I=0.005 kg.m^2 with radius R=0.050 m. The blocks are released from rest with the spring relaxed.i.e in its equilibrium position). (a) What is the combined(total) kinetic energy of the two blocks when the hanging two-block-pulley system has fallen a distance of 0.090 m? J (b) What is the rotational kinetic energy of the pulley when the hanging blockhas fallen 0.090 m? http://www.webassign.net/hrw/W0155-N.jpg ]2. Relevant equations[/b] Mass 1 Fnet(X)= [T[/1] -[F][/sp] =[M][/1][a][/x]= [T][/1] -KΔs Pulley [T][/net] =[T][/1]R -[T][/2]R= -IΩ Hanging Mass [F][/net]=[M][/2]-[T][/2]=[M][/2] 3. The attempt at a solution Three equations Four unknowns ,I do not know how to proceed from this point.