Kinetic energy, riddle me this

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SUMMARY

The discussion centers on the comparison between two experiments involving a gun: Experiment A, where a bullet is fired, and Experiment B, where no bullet is present. In Experiment A, the total energy is divided into E(heat) and E(projectile), while in Experiment B, only E(heat) is produced from the combustion of gunpowder. The key conclusion is that the energy associated with the projectile in Experiment A does not derive from E(heat) but rather from the high-pressure gas generated during combustion, which propels the bullet. This distinction clarifies that energy is not created from nothing in Experiment A; instead, it is transformed from the energy of expanding gases.

PREREQUISITES
  • Understanding of thermodynamics and energy conversion
  • Familiarity with the principles of combustion and gas expansion
  • Basic knowledge of projectile motion and forces
  • Concept of energy conservation in physical systems
NEXT STEPS
  • Study the laws of thermodynamics, particularly the first law regarding energy conservation
  • Explore the mechanics of gas expansion and its effects on energy transfer
  • Investigate the principles of projectile motion and how energy is imparted to a projectile
  • Examine combustion processes and their energy outputs in various scenarios
USEFUL FOR

Physics students, educators, and anyone interested in understanding the principles of energy transformation and mechanics in firearms and combustion processes.

quadcatfly
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Imagine two experiments A and B.

In experiment A I load a gun with a cartridge and shoot a bullet. Total energy in this experiment will be E(heat) + E(projectile). I include recoil in E(projectile). E(heat) in its turn will heat the muzzle and some air. Done.


In experiment B I do everything the same, except the is no bullet (e.g. no projectile). Same gun, same cartridge and the amount of gunpowder in it. So I pull the trigger. Total energy of this system will be E(heat) which will amount to the same level as in experiment A since I am burning the same amount of gunpowder under the same conditions.

I can't quite wrap my head around it.It turns out that in my experiment A I got E(projectile) out of nothing? Since it obviously didn't convert from E(heat) as clearly demonstrated by the experiment B.

Someone please enlighten me !
 
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quadcatfly said:
In experiment B I do everything the same, except the is no bullet (e.g. no projectile). Same gun, same cartridge and the amount of gunpowder in it. So I pull the trigger. Total energy of this system will be E(heat) which will amount to the same level as in experiment A since I am burning the same amount of gunpowder under the same conditions.

No you're not, there's no bullet in experiment B. In both cases you create high-pressure gas, which is going to expand. In the first case, most of the energy will go to the bullet, in the second case, all of the energy will end up moving the air in and in front of the barrel, and this energy will eventually up as extra heat.
 
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