UPS delivery man is loading his truck by shoving the parcels up a ramp. The ramp is inclined at an angle of 30 degrees above the horizontal. He sends a parcel of mass 15 kg, up this ramp. the coefficient of sliding friction is .10 and gravitational force is class standard (10). A The magnitude of the kinetic friction acting on the parcel is? B He sends parcel up ramp with initial Kinetic Energy, E, so that by the time, the parcels up the ramp, it has 0 KE. Ramp is length 1.0m. C To give this parcel this initial KE, he most do WORK on the parcel. Assuming he pushed it a short distance of .75m what is the average force he needs to apply. Ignore friction for this part. The work I have done is: A Y Components: N-MG Cos 30 --> N=150 Cos 30 --> N=129.9 Friction = [tex]\mu[/tex]k * N --> .10 * 129.9 ---> Magnitude =12.99 B 1/2 M Vo2+ [STRIKE]MGH[/STRIKE]= [STRIKE]1/2 M Vf2[/STRIKE] + MGH 1/2 M Vo2 = MGH H= Sin30 -->.5 1/2 (15) (V)2= 75 V=3.16 So initial KE = 75 ????? C Is related to B so if that's wrong this is wrong. Work = Force * Displacement Work = KE KE: 75 / Disp: .75 = Force: 100N Thanks for your help.