L-edge of Absorption Explained - Si L2,3 Edge at 99.8 eV

  • Thread starter Thread starter DivGradCurl
  • Start date Start date
  • Tags Tags
    Absorption
DivGradCurl
Messages
364
Reaction score
0
What is the L-edge of absorption? For example, Si has its L2,3 edge at 99.8 eV? The second atomic shell is L, but what does 2,3 mean?

Thanks
 
Physics news on Phys.org
The k-edge and L edge of an atom refers to the minimum energy (or maximum wavelength) photon (UV or x-ray) that can remove an (photo) electron from the K or L shells (usually meaning ionize), such that other bound electrons cascade down to fill the vacancies. The photon energies correspond to "edges" in a plot of photon attenuation vs. photon energy where there is a sudden large increase in the attenuation coecfficient. Figure 1 in this reference shows a k-shell photoelectron ejection, with the possible atomic electron cascades.
http://www.bruker-axs.de/fileadmin/user_upload/xrfintro/sec1_1.html
L(2,3) may refer to the electron transition that fills the L shell vacancy (M-shell to L-shell)
 
Last edited:
Thanks for the reply, Bob. That's a very nice reference, and now I understand.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top