Lab Help, Heat of Fusion and Specific Heat?

[fuzmaster]

Homework Statement

Were doing this lab that is related to finding the specific heat and heat of fusion of water. To put the lab simply we filled aluminum calorimeters with water that's around 35°C. After that we took a handful of ice and it into the calorimeter full of water and measured the temperature after stirring with the lid on and finding out the temperature after the ice is melted. Heres the data.

Mass of Calorimeter Cup
Trial 1: .04889 kg Trial 2:.0464 kg
Mass of Calorimeter Cup and Water
Trial 1: .18574 kg Trial 2:.2213 kg
Mass of Calorimeter Cup and Water (after Ice is Melted)
Trial 1: .23135 kg Trial 2:.2693 kg
Temperature of Water and Calorimeter, Initial
Trial 1: 35.6°C Trial 2:35.5°C
Temperature of Water and Calorimeter, Final
Trial 1: 4.2°C Trial 2:10.4°C


Now we have to calculate our results in different forms. But their are several things that I don't know how to get. One is the joules lost by calorimeter and by lost by water. Also the Joules used to warm water formed by melted ice, used to melt the Ice, and the Heat of fusion. How do I get these answers?

Homework Equations

Q=CpMT, T is temperature, Cp is Specific Heat

The Attempt at a Solution

Which mass should I use and what's the heat of fusion formula

 

[mgb_phys]

You assume no energy is lost, so adding ice to warm water you have:
energy of ice melting + energy of ice-water warming = energy of warm water cooling + energy of warm calorimeter cooling.

For the water and metal changing temperature you have to equation Q=cmt , for the ice melting there is no temperature change so Q = m * heat_fusion.

You first need to calculate the masses of the warm water, the ice and the calorimeter.
You will also need the specific heat of water and aluminium, and the heat of fusion of water

 

[nlightner]

Hi there,

It seems like you are conducting a lab experiment to determine the specific heat and heat of fusion of water. Based on the data you have provided, it looks like you have done the experiment correctly. Here are some steps to help you calculate the required values:

1. Calculate the mass of water used in each trial by subtracting the mass of the calorimeter cup from the mass of the calorimeter cup and water.

2. Calculate the change in temperature (∆T) by subtracting the final temperature from the initial temperature.

3. Use the equation Q = mC∆T to calculate the heat lost by the calorimeter and the heat lost by the water. Remember to use the mass of water in your calculations.

4. To calculate the heat used to warm the melted ice, use the equation Q = mC∆T again, but this time use the mass of water formed by the melted ice and the change in temperature from the final temperature to the initial temperature.

5. To calculate the heat used to melt the ice, use the equation Q = mL, where L is the heat of fusion of water (334 J/g). Use the mass of ice (which is equal to the mass of water formed by the melted ice) in your calculation.

6. Finally, to calculate the heat of fusion, use the equation Q = mL once again, but this time use the mass of ice and the change in temperature from the final temperature to the initial temperature.

I hope this helps. Good luck with your calculations!