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Lab Help, Heat of Fusion and Specific Heat?

  • Thread starter fuzmaster
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Homework Statement


Were doing this lab that is related to finding the specific heat and heat of fusion of water. To put the lab simply we filled aluminum calorimeters with water that's around 35°C. After that we took a handful of ice and it into the calorimeter full of water and measured the temperature after stirring with the lid on and finding out the temperature after the ice is melted. Heres the data.

Mass of Calorimeter Cup
Trial 1: .04889 kg Trial 2:.0464 kg
Mass of Calorimeter Cup and Water
Trial 1: .18574 kg Trial 2:.2213 kg
Mass of Calorimeter Cup and Water (after Ice is Melted)
Trial 1: .23135 kg Trial 2:.2693 kg
Temperature of Water and Calorimeter, Initial
Trial 1: 35.6°C Trial 2:35.5°C
Temperature of Water and Calorimeter, Final
Trial 1: 4.2°C Trial 2:10.4°C


Now we have to calculate our results in different forms. But their are several things that I don't know how to get. One is the joules lost by calorimeter and by lost by water. Also the Joules used to warm water formed by melted ice, used to melt the Ice, and the Heat of fusion. How do I get these answers?


Homework Equations


Q=CpMT, T is temperature, Cp is Specific Heat



The Attempt at a Solution



Which mass should I use and whats the heat of fusion formula
 

Answers and Replies

  • #2
mgb_phys
Science Advisor
Homework Helper
7,774
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You assume no energy is lost, so adding ice to warm water you have:
energy of ice melting + energy of ice-water warming = energy of warm water cooling + energy of warm calorimeter cooling.

For the water and metal changing temperature you have to equation Q=cmt , for the ice melting there is no temperature change so Q = m * heat_fusion.

You first need to calculate the masses of the warm water, the ice and the calorimeter.
You will also need the specific heat of water and aluminium, and the heat of fusion of water
 

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