Lab report: pulling cart up a ramp, find efficiencies

Click For Summary
The lab report discusses pulling a cart up a ramp to calculate efficiencies but indicates issues with results and calculations. The experiment involved varying masses and ramp angles, using a spring scale to measure force in Newtons. The reported efficiencies exceed 100%, suggesting calculation errors, particularly regarding the formulas for total work input and useful work output. Key points of confusion include whether the mass of the cart was included and the correct conversion of grams to kilograms. Addressing these calculation errors should help resolve the discrepancies in the report.
msimard8
Messages
58
Reaction score
0
I am doing a lab report and something is wrong. I don't know if it is my results, or if it is my calculation.

What we did was pull a cart up a ramp upside down (wheels facing up) with different masses and different angles of the ramp. We pulled it up with a spring scale calibrated in Newtons. The Newtons were recorded and the height, distance, and angle of the ramp were in this chart. The sigificant digits are off but that shouldn't affect the results I am getting. The efficiencies are way over 100% which is maximum.

Formulas that I used are

Total Energy Input = force x distance
Useful Energy Output = mass x gravitational energy x height
Efficency = Energy output/ energy input x 100%



The chart is not complete yet though.
 

Attachments

Physics news on Phys.org
msimard8 said:
Total Energy Input = force x distance
Useful Energy Output = mass x gravitational energy x height
Efficency = Energy output/ energy input x 100%

I have to fix your words here-- this should read:

total work input = force x distance
useful work output = mass x gravitational field strength x height


I haven't seen the chart yet (approval is pending) but let me take a few stabs:
did you include the mass of the cart itself? (you should have)
did you multiply the weight of the cart (in Newtons) times "g"? (you should NOT have)
did you convert grams to kilograms correctly? (200 g = 0.200 kg)
 
thanks

problem solved
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
18
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
11K
Replies
4
Views
3K
  • · Replies 5 ·
Replies
5
Views
15K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K