When using Fourier's trick for determining the allowable energies for stationary states, Griffiths introduces the a+- operators. When factoring the Hamiltonian, the imaginary part is assigned to the momentum operator versus the position operator. Is there a reason for this? If :(adsbygoogle = window.adsbygoogle || []).push({});

a-+ = k(ip + mwx)(-ip + mwx), and the commutator is (xp-px), Is

a+- = k(-ip = mwx)(ip + mwx) ?

If so, is the commutator (px-xp)?

Thanks in advance for your input.

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# Ladder operators and the momentum and position commutator

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