sgh1324
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A sphere is rolling inclined wall (θ radian).
and the momentum of that sphere is
L = 1/2 mv^2 + 1/5 mv^2 + mgx sin(θ) = 7/10 m v^2 + mgx sin(θ)
∂L/∂v = p
7/5 m v = p
but I can't understand why the factor of mv is 7/5.
p is the linear momentum of sphere.
which means the factor of mv must be always 1 (my thought)
p = mv
↑that was an unchanging truth of my physical world.
why rolling effect to the momentum? angular momentum of the sphere has no relation with p direction!
and the momentum of that sphere is
L = 1/2 mv^2 + 1/5 mv^2 + mgx sin(θ) = 7/10 m v^2 + mgx sin(θ)
∂L/∂v = p
7/5 m v = p
but I can't understand why the factor of mv is 7/5.
p is the linear momentum of sphere.
which means the factor of mv must be always 1 (my thought)
p = mv
↑that was an unchanging truth of my physical world.
why rolling effect to the momentum? angular momentum of the sphere has no relation with p direction!
