Lagrangian of system with circle and cube

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SUMMARY

The discussion focuses on deriving the Lagrangian for a system involving a bead moving along a circular path and a cube of mass M. The Lagrangian is defined as L = U - V, where U represents kinetic energy and V represents potential energy. The user expresses confusion regarding the inclusion of the bead's mass m in the kinetic energy terms and seeks clarification on the correct formulation of the Lagrangian. The solution involves expressing the bead's position in terms of generalized coordinates and differentiating to find velocity.

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Oomph!
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Hello. I have some problems with making Lagrangian. I need your advice.

1. Homework Statement

I have this situation:
situation2.png


Consider the circular path is intangible and without friction. I have to find Lagrangian for coordinates x and θ.

Homework Equations


[/B]
L = U - V

The Attempt at a Solution



I know the result from a book:
result.png


The origin of the coordinate system is at the center of the initial position of the circular trajectory.

I understand that the fist part is kinetic energy of big cube of mass M in coordinate x.The second part is kinetic energy of bead of mass m in a circle in coordinate x.
I don't understand to third part. I think that the m (mass of bead) is missing there. If I will consider that m is there, it is kinetic energy of bead in coordinate θ.
What is the poind of fourth part? I don't see it.
The last part is potentional energy of bead, I understand.

I wrote it there:
lagrangian3.png



So, could you tell me, if this Lagrangian right? And if it is not, how it has to look?
Thank you.
 

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I suggest you write the position of the bead (both horizontally and vertically) as a function of the generalised coordinates. Differentiating it wrt time will give you the velocity.
 

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