Laplace equation for parallel plate condersers

[gulsen]

I've recently started studying Laplace's equation and it's solution under various simple circumstances in electrostatics. I tried to solve the equation for a parallel plate condenser system, but I couldn't meet the boundary conditions. I had two plates, one placed on xz plane at y=0 (with potential = 0), second parallel to it, at y=d (with potential $V_0$). I placed them such that they're symmetrical in x and z, i.e., y-axis crosses midpoints of plates; therefore the potential should be an even function of x and z. Noting that $V(0,0,0) = 0$ I wrote the solution:

$$A\cosh(kx) \cosh(lz) \sinh(my)$$
with $$k^2 + l^2 + m^2 = 0$$ and let $A$ be any complex number.

I assumed that potential should drop to zero when $x,z \to \pm \infty$, and this's the boundary condition that doesn't meet with my "solution".

Can anyone help me working out the solution, or forward me to some resource on it?
Thanks!

 

[lpfr]

Your formula cannot fit the potential. Of course, k and l are zero (because of symmetry the potential does not depends on x or z).
But the potential in this problem is a linear function of y. There is no way to fit a sinh into a straight line.
Then your assumption about the mathematical form of the solution is wrong.
Let's start with Laplace's equation:

$${\partial^2 \varphi\over \partial x^2 } +<br /> {\partial^2 \varphi\over \partial y^2 } +<br /> {\partial^2 \varphi\over \partial z^2 } = 0.$$

The first and third terms are zero. Then:
$${\partial^2 \varphi\over \partial y^2 }= 0.$$

Then: $$\varphi = ay+b$$

 

[gulsen]

This can't be true because plates are not infinite, and field lines are no longer straight lines when we approach to the edges:

http://www.regentsprep.org/Regents/physics/phys03/aparplate/plate2.gif

And how do we say potential itself does not depend on x either z? Apparently they do --even though the assumption that field lines were straight, they should vanish in the outside region between plates, which is defined by x and y.

I remember this problem is not easily solved (possibly from Feynman lectures)

 

[lpfr]

Well, if you had said that the plates where finite. I wouldn't have bothered to answer.
This problem, as Feynman said is not soluble analytically.