use laplace transforms to solve the differential equation
y"+2y'+17y = 1
Initial conditions are
y(0) = 0
y'(0) = 0
The Attempt at a Solution
so it converts to Y(s) (s^2+2s+17) = 1/s
which then ends up as;
Y(s) = 1/s*1/(s^2+2s+17)
i know i need to invert the equation from laplace again but not sure how.
Im not sure if im on the right track by re-arranging to 1/s((s+1)^2+4^2)?
Still getting used to spotting laplace eqns.
and help would be much appreciated.