Laplace Transform of cos(kt) using Power Series expansion

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Homework Help Overview

The discussion revolves around finding the Laplace Transform of cos(kt) using its power series expansion rather than the standard formula for periodic functions. The original poster outlines the relevant equations and expresses difficulty in integrating the resulting series after applying the Laplace Transform formula.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the integration of the power series term by term and suggest using integration by parts or deriving a formula for the Laplace Transform of t^(2n). There are also considerations about differentiating the integral with respect to s to simplify the process.

Discussion Status

The discussion is active, with participants providing guidance on potential methods for integration and exploring different approaches. Some participants are questioning the need for mathematical induction, suggesting alternative methods to derive the necessary formulas.

Contextual Notes

There is a mention of the original poster's background in theoretical physics, indicating that they have not yet learned mathematical induction, which may affect their approach to the problem.

eyenkay
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Homework Statement


The problem just states to find the Laplace Transform of cos(kt) from its power series expansion, instead of using the formula for the transform of a periodic function.

Homework Equations


Equation for Laplace transform of a function f(t) ->\int(e^{-st}f(t))dt
Power Series Expansion for cos(x)-> \sum\frac{(-1)^{n}}{(2n)!}x^{2n}

The Attempt at a Solution


I've been trying to apply the formula for the Laplace Transform directly to the expansion of cos, but I get stuck in the integration.. Once you apply the formula, I figured you can bring the e^{-st} inside the sum since it doesn't depend on n, and therefore you treat it like a constant wrt the sum. Then interchange the order of the sum and the integral, and end up with \sum\frac{(-1)^{n}}{(2n)!}k^{2n}\int(e^{-st}t^{2n})dt..
This is what I can't figure out how to integrate, if you try it by parts you just get t to the 2n-1, then 2n-2... etc.
Any ideas?
 
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You've got it down to the laplace transform of a power t^(2n). If you don't have a formula that you can use for it, then you derive it just as you say. Use integration by parts and induction to find the formula. Start by doing t, t^2, t^3... It should be pretty obvious what the formula for t^(2n) looks like. Hint: the answer will have a factorial in it.
 
You can also compute the integral of exp(-s t) and then differentiate that 2n times w.r.t. s to bring down a factor t^(2n) in the integrand.
 
oh..ok i see, i was forgetting to input the bounds, this causes each term to go to zero except for the last one, where the exponent of t is 0. Thanks.
 
Dick said:
You've got it down to the laplace transform of a power t^(2n). If you don't have a formula that you can use for it, then you derive it just as you say. Use integration by parts and induction to find the formula. Start by doing t, t^2, t^3... It should be pretty obvious what the formula for t^(2n) looks like. Hint: the answer will have a factorial in it.
Hi I'm a physics student studying theoretical physics 2, we haven't learned math induction. Is there another way around it?

What about applying the formula

| exp(- sigma t) f(t) | = Mthanks!
 

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