Laplace Transform of t cos(2t)

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Homework Help Overview

The problem involves finding the Laplace Transform of the function f(t) = t cos(2t) using its definition.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss integration by parts as a method to tackle the integral, with one participant expressing difficulty in progressing with their initial setup. Another suggests a different approach to splitting the integral, which leads to a successful resolution for one participant.

Discussion Status

The discussion has seen participants exploring various methods for integration by parts, with at least one participant successfully applying a suggested approach. There is also mention of an alternative method involving the derivative of the Laplace Transform.

Contextual Notes

Participants are navigating the complexities of integration by parts and the application of Laplace Transform properties, indicating a level of uncertainty in the initial setup and assumptions about the integral's behavior.

rhololkeolke
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Homework Statement


Find the Laplace Transform from the definition of f(t) = tcos(2t)


Homework Equations


\int e^-^s^ttcos(2t)dt


The Attempt at a Solution


I started by doing parts
u = t
du = dt

dv = cos(2t)e^-^s^t dt

but I get stuck on v and as far as I can tell doing parts on v won't help because neither term will be reduced when differentiated.

I'm looking for some direction on how to solve this integral.
Thanks!
 
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You might try splitting it up differently. Try

\begin{align*}<br /> u &amp; = t e^{-st} \\<br /> dv &amp; = \cos 2t<br /> \end{align*}<br />

You'll have to integrate by parts at least twice.
 
Thanks. I was able to figure it out after starting with it split how you suggested.
 
A sneaky way is to use the fact that L[t f(t) ] = - F^{\prime}(s). You can use the fact that L[ \cos (2t) ] = \frac{s}{s^2 + 4} for s>0. This way you are taking a derivative instead of integrating!
 
Last edited:

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