- #1
Chacabucogod
- 56
- 0
I was wondering whether this can be done:
Let's say you have transfer function that goes like this:
[tex]\frac{Y(s)}{U(s)}= \frac{N(s)}{D(s)}[/tex]
Now let's say I divide my transfer into two:
[tex]\frac{Y(s)}{Z(s)}= N(s)[/tex]
[tex]\frac{Z(s)}{U(s)}= \frac{1}{D(s)}[/tex]
Can I apply the Laplace Inverse to these two equation separately and then substitute the value of z(t) on one?
[tex]D(s)Z(s)=U(s)[/tex]
[tex]N(s)Z(s)=Y(s)[/tex]
Thank you!
Let's say you have transfer function that goes like this:
[tex]\frac{Y(s)}{U(s)}= \frac{N(s)}{D(s)}[/tex]
Now let's say I divide my transfer into two:
[tex]\frac{Y(s)}{Z(s)}= N(s)[/tex]
[tex]\frac{Z(s)}{U(s)}= \frac{1}{D(s)}[/tex]
Can I apply the Laplace Inverse to these two equation separately and then substitute the value of z(t) on one?
[tex]D(s)Z(s)=U(s)[/tex]
[tex]N(s)Z(s)=Y(s)[/tex]
Thank you!