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Laplace Transform Solution

  1. Mar 30, 2015 #1
    I was wondering whether this can be done:

    Let's say you have transfer function that goes like this:

    [tex]\frac{Y(s)}{U(s)}= \frac{N(s)}{D(s)}[/tex]

    Now let's say I divide my transfer into two:

    [tex]\frac{Y(s)}{Z(s)}= N(s)[/tex]

    [tex]\frac{Z(s)}{U(s)}= \frac{1}{D(s)}[/tex]

    Can I apply the Laplace Inverse to these two equation separately and then substitute the value of z(t) on one?

    [tex]D(s)Z(s)=U(s)[/tex]

    [tex]N(s)Z(s)=Y(s)[/tex]

    Thank you!
     
  2. jcsd
  3. Mar 30, 2015 #2

    Hesch

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    Gold Member

    Of course you can:

    You then have:

    Y(s)/U(s) = (N(s)*Z(s) ) / (D(s)*Z(s) ) => (shorten right fraction)

    Y(s)/U(s) = N(s)/D(s)

    No problem, assuming that Z(s) ≠ 0.
     
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