Laplace transform with step function

[CINA]

Homework Statement

y'+2y=f(t), y(0)=0, where f(t)=\left\{t, 0\leq t<0 \;and \; 0, t \geq 0 (I don't know how to do piecewise)

Homework Equations

Equation for initial conditions; step function: u(t-a)

The Attempt at a Solution

I know how to solve a differential equation with initial conditions using Laplace transforms, I just don't know what f(t) looks like as a step function, or how it would behave. would it be t*u(t-1)?

 

[hunt_mat]

f(t) looks like 0 for all values of t, are you sure your definition of f(t) is correctly copied down?

 

[CINA]

Opps, it's:
t, \; 0 \leq t < 1
0, \; t \geq 1

 

[hunt_mat]

OKay, then when taking the Laplace transform of the RHS, split the domain of integration to (0,1) and [1, infintity], the part where you integrate over 0 to infinity will vanish and you will be left with:
<br /> \int_{0}^{1}te^{-st}dt<br />