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Laplace transforms to solve initial value DE / partial fractions

  1. Sep 20, 2013 #1
    Hey guys, i have read many posts on physics forums but this would be my first post. I am quite stuck so any help would be much appreciated.

    1. The problem statement, all variables and given/known data

    Use Laplace transforms to solve the initial value problem:

    f''(y) + 4f'(y) +8y = u(t-1) where y(0) = 1 and y'(0) = -1

    Solve this problem using laplace transforms, showing all steps in your reasoning. State the solution y(t) for each of 0<t<1 and t>1, then sketch it over the range 0<= t <= 10, noting its main features.

    2. Relevant equations



    3. The attempt at a solution

    I have gotten up to F(Y) = (e^-s + s^2 + 3s)/(s(s^2 + 4s+8))

    However, from here i am not sure what to do. I tried taking the partial fractions of:

    1/(s(s^2 + 4s+8))

    but am getting very confused. Again any help would be much appreciated. Cheers
     
  2. jcsd
  3. Sep 21, 2013 #2

    SteamKing

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    Why don't you break F(Y) down into the sum of its various components?

    E.g., D = (s(s^2+4s+8))

    F(Y) = (e^-s)/D + s^2/D + 3s/D

    You can tackle each term individually.

    PS: finding the PFE of 1/D doesn't help.
     
  4. Sep 21, 2013 #3

    HallsofIvy

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    The denominator is [tex]s(s^2+4s+ 8)= s(s^2+ 4s+ 4+ 4)= s((s+ 2)^2+ 4)[/tex] so you can use "partial fractions to write that as [tex]\frac{A}s+ \frac{Bs+ C}{(s+2)^2+ 4}[/tex].
     
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