Laplace's Equation Solution in 2D

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SUMMARY

The discussion focuses on solving Laplace's equation in two dimensions using separation of variables and superposition. The user proposes a solution of the form u = u_1 + u_2, where u_1 and u_2 correspond to different boundary conditions. The consensus confirms that this approach is valid due to the linearity of Laplace's equation, allowing for the application of the superposition principle to combine solutions that meet distinct boundary conditions.

PREREQUISITES
  • Understanding of Laplace's equation and its properties
  • Familiarity with separation of variables technique
  • Knowledge of boundary conditions in partial differential equations
  • Concept of superposition principle in linear equations
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  • Study the method of separation of variables in more detail
  • Explore the application of boundary conditions in solving PDEs
  • Learn about the superposition principle in linear differential equations
  • Investigate numerical methods for solving Laplace's equation
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Mathematicians, physicists, and engineers involved in solving partial differential equations, particularly those working with Laplace's equation in two-dimensional domains.

neutrino2063
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I am using separation of variables and superposition to solve:

u_{xx}+u_{yy}=0; <br /> for (x,y) \in (0,L) X (0,H)
u(0,y)=f(y);<br /> u(L,y)=0;<br /> u(x,0)=g(x);<br /> u(x,H)=0

Is it correct to assume that I can write my solution as:
u=u_1+u_2

Where:
u_1
is the solution with BC
u(0,y)=0;<br /> u(L,y)=0;<br /> u(x,0)=g(x);<br /> u(x,H)=0

And:
u_2
is the solution with BC
u(x,0)=0;<br /> u(x,H)=0;<br /> u(0,y)=f(y);<br /> u(L,y)=0
 
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neutrino2063 said:
I am using separation of variables and superposition to solve:

u_{xx}+u_{yy}=0; <br /> for (x,y) \in (0,L) X (0,H)
u(0,y)=f(y);<br /> u(L,y)=0;<br /> u(x,0)=g(x);<br /> u(x,H)=0

Is it correct to assume that I can write my solution as:
u=u_1+u_2

Where:
u_1
is the solution with BC
u(0,y)=0;<br /> u(L,y)=0;<br /> u(x,0)=g(x);<br /> u(x,H)=0

And:
u_2
is the solution with BC
u(x,0)=0;<br /> u(x,H)=0;<br /> u(0,y)=f(y);<br /> u(L,y)=0

Yes, your assumption looks fine; because Laplace's equation is linear, any solution to it will obey the superposition principle. This means that if you find one solution that satisfies one set of boundary conditions, and another solution that satisfies a different set of boundary conditions, The superposition of the two solutions will satisfy the sum of the two sets of boundary conditions.
 

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