- #1

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"the pump laser delivers 500-μJ pulses at 1.064 μm with a 12.5-kHz repetition rate"

Thank you for your time.

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- Thread starter vivek.iitd
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- #1

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"the pump laser delivers 500-μJ pulses at 1.064 μm with a 12.5-kHz repetition rate"

Thank you for your time.

- #2

Drakkith

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You can find the power output by multiplying the pulses per second by the energy per pulse. I don't know exactly what you mean by "temporal profile" though.

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- #3

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By temporal profile i mean, as this is a pulsed laser, so how the power of a pulse will vary as a function of time. If we consider it to be a Gaussian, then we can write it like

P = Po*exp(-(t/T)^2) where Po is the peak power as calculated above and T is FWHM.

Am i right?

- #4

Drakkith

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Thank you for your reply, as you said multiplying Energy per pulse and repetition rate will give me Average power. And if i have pulse duration = 20ns, then Pulse energy*pulse duration will give me Peak power right?

I think it depends on if the 500 microjoules is an "average" or not. If you apply 100 joules for the first and last 10% of the pulse, but 700 joules for the rest, your peak power will not be the same as it would be if it is a steady 500 for the entire pulse.

By temporal profile i mean, as this is a pulsed laser, so how the power of a pulse will vary as a function of time. If we consider it to be a Gaussian, then we can write it like

P = Po*exp(-(t/T)^2) where Po is the peak power as calculated above and T is FWHM.

Am i right?

I'm not sure honestly, but I don't think there's enough information to figure out the temporal profile. But you could assume a profile if you want to. Someone else will have to look at the equations though, I'm not familiar with them.

- #5

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Thanks.

- #6

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Almost. To calculate Po, you need to set the integral of that expression equal to the pulse energy, 500 uJ.

By temporal profile i mean, as this is a pulsed laser, so how the power of a pulse will vary as a function of time. If we consider it to be a Gaussian, then we can write it like

P = Po*exp(-(t/T)^2) where Po is the peak power as calculated above and T is FWHM.

Am i right?

- #7

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okay thank you.

- #8

Claude Bile

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Pulse energy*pulse duration will give me Peak power right?

Think about this for a moment. This suggests that the longer the pulse duration, the higher the peak power. Clearly this is not correct. Instead it is the

If in doubt, consider the units involved. Power = Energy/time.

Also, you cannot calculate the temporal profile with the information given in the original post. We can calculate some integrals, but that is about it. One would need to use a fast detector and an oscilloscope to measure the intensity profile of such a laser as a function of time.

Claude.

- #9

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ohh sorry, yes it should be Power=Energy per pulse/Pulse duration.

- #10

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https://www.physicsforums.com/showthread.php?t=547779

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