Latent heat of vaporisation question

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SUMMARY

The discussion focuses on calculating the heat capacity of a flask and the mass of water collected during boiling. The pupil determined that with a heat supply of 16W over 30 minutes, the total heat supplied is 28,800J, leading to an estimated upper limit for the heat capacity of the flask and its contents at 360 J/K. Additionally, the latent heat of vaporization for water is given as 2.26 x 10^6 J/kg, which is essential for calculating the mass of water collected when the power supply is increased to 60W.

PREREQUISITES
  • Understanding of latent heat of vaporization (lv of water = 2.26 x 10^6 J/kg)
  • Basic principles of thermodynamics and heat transfer
  • Ability to perform calculations involving power, energy, and time
  • Familiarity with units of measurement in physics (Joules, Watts, kilograms)
NEXT STEPS
  • Calculate the mass of water collected after 30 minutes at a power supply of 60W using the formula: mass = total heat supplied / latent heat of vaporization.
  • Explore the concept of specific heat capacity and its applications in thermal systems.
  • Investigate the effects of varying power supplies on the rate of evaporation and heat transfer efficiency.
  • Learn about experimental methods for measuring heat capacity and latent heat in laboratory settings.
USEFUL FOR

Students studying thermodynamics, physics educators, and anyone interested in practical applications of heat transfer and energy calculations.

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Homework Statement


A pupil performing an experiment finds that, when the heat supply is 16W, it takes 30 mins for the temp of the water to rise from 20°C to 100°C, and that the rate of evap is very
slow even at the latter temp. Estimate an upper limit to the value of the heat capacity of the inner flask and its contents. Calculate the mass of water collected after 30mins of steady boiling when the power supply is 60W.

(lv of water = 2.26 x 10^6 J/Kg)



The attempt at a solution

For the upper limit i did this
total heat supplied= 16 x 30 x 60= 28,880J

C= E/Δt= 28,800/80 = 360 J/K.

Now for the mass of water I get confused with what to do
 
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Does the problem as reproduced here on this forum include all the information provided in the original problem statement?
 
Nevermind I figured it out. xD
 

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