1. The problem statement, all variables and given/known data A .5 kg block is dropped from 15m. A 5 gram bullet hits the block at 233 m/s. At what height must the block be hit to completely stop the blocks freefall momentarily. 2. Relevant equations p=mv 1/2mv^2=mgh 3. The attempt at a solution bullets ke 1/2(.005)(233)^2=.5(9.8)(h) When the bullets kenetic energy is equal to the blocks potential it will momentarily pause in mid air. Atleast i thought. bullet's ke = 135.72 joules= blocks pe = 27.698m The block would have to be 27 meters above the ground to have as much potential energy as the bullet described. Then i was thinking of solving it using momentum but im not sure how that would work out.