MHB LCM of 22x32x4 and 23x3: Explained

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The Lowest Common Multiple of 22x32x4 and 23x3
 
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Do you have any ideas on how this problem may be approached?
 
greg1313 said:
Do you have any ideas on how this problem may be approached?

There is 2 answer
(a) 144 (e) 24 𝑋 32 How can i get this answer
 
prasadini said:
There is 2 answer
(a) 144 (e) 24 𝑋 32 How can i get this answer

Sorry for dumb question, but how is 144 a multiple of 22x32x4? isn't 144<22x32x4??
 
prasadini said:
There is 2 answer
(a) 144 (e) 24 𝑋 32 How can i get this answer

You need to start showing you have at least thought about the problem before posting.
 
prasadini said:
The Lowest Common Multiple of 22x32x4 and 23x3

I would begin by writing the prime factorizations of both numbers:

$$22\cdot32\cdot4=(2\cdot11)(2^5)(2^2)=2^8\cdot11$$

$$23\cdot3=3\cdot23$$

Now, combine the prime factors from both, using the higher power of each prime factor found in either, to get the LCM, which we'll call $N$:

$$N=2^8\cdot3\cdot11\cdot23=194304$$

Since the two given numbers are co-prime, we find their LCM to simply be their product. :D
 
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