Length Contraction of Bridge rotated 30 degrees

Click For Summary
The discussion revolves around calculating the length of a bridge observed from a train moving at a velocity of 1/4c, with the bridge oriented at a 30-degree angle. The proper length of the bridge is 20 meters in its own reference frame, but the observed length from the train's perspective is affected by length contraction. Participants clarify that there is no contraction in the y-direction, while contraction occurs in the x-direction, leading to a calculated length of approximately 19.526 meters. The conversation also touches on the use of Lorentz transformations and the importance of algebraic manipulation over simple arithmetic in solving such problems. The final consensus is that the correct approach involves applying the Lorentz transformation to derive the observed length efficiently.
  • #31
PeroK said:
It seems to me that your teacher is doing what I tried to do in post #8: help you to do a mathematical solution to the problem and not just plug numbers into a calculator. In particular, he/she wants you to use the matrix form of the Lorentz Transformation. In this case, this is simply a 2x2 matrix acting on 2D vectors.

If you really have a problem with the maths - algebra as "gymnastics" and matrices as "ugly" - then you need to sort this out. You might start by locking away your pocket calculator for a week or two!
I can find L^2 by doing a lorentz transformation on x and leave y alone with a 2x2 matrix, and then multiply by L0vector components,
if that is what you mean.
Just don't see how that is a 'extension to 4-vectors'
 
Physics news on Phys.org
  • #32
marimuda said:
I can find L^2 by doing a lorentz transformation on x and leave y alone with a 2x2 matrix, and then multiply by L0vector components,
if that is what you mean.
Just don't see how that is a 'extension to 4-vectors'

Technically, you would extend your 2x2 matrix to a 4x4 matrix with 1 in the (3,3) and (4,4) positions and 0 everywhere else. That would transform ##t## and ##x## as before and leave ##y## and ##z## unchanged.

A 4-vector is, by definition, something that transforms according to Lorentz. ##(ct, x, y, z)## is a 4-vector. Where motion is in the x-direction only, this is essentially no different from transforming ##x##, leaving ##y## unchanged and ignoring ##z##.

I think you need to check with your teacher what he/she is expecting. We're just guessing here.
 
  • Like
Likes marimuda

Similar threads

  • · Replies 36 ·
2
Replies
36
Views
3K
Replies
3
Views
2K
  • · Replies 38 ·
2
Replies
38
Views
4K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
9
Views
1K
  • · Replies 3 ·
Replies
3
Views
559
Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
11
Views
3K