Length Contraction of Bridge rotated 30 degrees

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Homework Help Overview

The discussion revolves around the concept of length contraction in special relativity, specifically regarding a train moving at a velocity of 1/4 the speed of light (c) as it passes under a bridge that is oriented at a 30-degree angle to the railway. The original poster seeks to calculate the perceived length of the bridge from the train's reference frame, given that the bridge's proper length is 20 meters.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the Lorentz factor and its implications for length contraction, questioning the calculations and assumptions made regarding the bridge's length in different reference frames. There are inquiries about the contraction factors in both the direction of travel and perpendicular to it. Some participants suggest using algebraic methods to simplify the problem-solving process.

Discussion Status

The discussion is ongoing, with various participants providing intermediate computations and corrections. Some guidance has been offered regarding the use of Lorentz transformations and the concept of proper length. There is an exploration of different methods to approach the problem, including the potential use of 4-vector notation.

Contextual Notes

Participants note the absence of a formal course on special relativity, which may affect their understanding and approach to the problem. There is also mention of the need for clarity in mathematical notation and the relevance of specific angles and velocities in the calculations.

  • #31
PeroK said:
It seems to me that your teacher is doing what I tried to do in post #8: help you to do a mathematical solution to the problem and not just plug numbers into a calculator. In particular, he/she wants you to use the matrix form of the Lorentz Transformation. In this case, this is simply a 2x2 matrix acting on 2D vectors.

If you really have a problem with the maths - algebra as "gymnastics" and matrices as "ugly" - then you need to sort this out. You might start by locking away your pocket calculator for a week or two!
I can find L^2 by doing a lorentz transformation on x and leave y alone with a 2x2 matrix, and then multiply by L0vector components,
if that is what you mean.
Just don't see how that is a 'extension to 4-vectors'
 
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  • #32
marimuda said:
I can find L^2 by doing a lorentz transformation on x and leave y alone with a 2x2 matrix, and then multiply by L0vector components,
if that is what you mean.
Just don't see how that is a 'extension to 4-vectors'

Technically, you would extend your 2x2 matrix to a 4x4 matrix with 1 in the (3,3) and (4,4) positions and 0 everywhere else. That would transform ##t## and ##x## as before and leave ##y## and ##z## unchanged.

A 4-vector is, by definition, something that transforms according to Lorentz. ##(ct, x, y, z)## is a 4-vector. Where motion is in the x-direction only, this is essentially no different from transforming ##x##, leaving ##y## unchanged and ignoring ##z##.

I think you need to check with your teacher what he/she is expecting. We're just guessing here.
 
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