L'Hopital's Rule for Solving Indeterminate Form (-∞)/∞

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Homework Help Overview

The discussion revolves around the application of L'Hopital's Rule to the indeterminate form (-∞)/∞, exploring whether this form can be treated similarly to the more commonly discussed 0/0 form. Participants are also engaging in a side conversation about the notation for mathematical symbols.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants are questioning the applicability of L'Hopital's Rule to the (-∞)/∞ form, while others suggest that it can be used for various indeterminate forms beyond just 0/0. There is also a discussion about the proper notation for mathematical symbols in the context of the forum.

Discussion Status

The discussion is ongoing, with differing opinions on the applicability of L'Hopital's Rule to the (-∞)/∞ form. Some participants have provided insights into the rule's broader applicability, while others are still exploring the foundational concepts behind it.

Contextual Notes

Participants are navigating the nuances of L'Hopital's Rule and its conditions, with some uncertainty about the assumptions required for its application. There is also a mention of notation practices within the forum, indicating a potential barrier for some users in expressing mathematical concepts.

kasse
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Can one use L'Hopital's Rule on the indeterminate form (-∞)/∞ ?

And by the way, is there a way to write mathematical signs like ∞, the integral sign etc except google-ing, cutting and pasting?
 
Last edited:
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I think you can. It would probably be:

[tex]-\lim_{x\rightarrow c} \frac{f(x)}{g(x)}[/tex] so that both functions approach [tex]\infty[/tex]

you write those signs in [tex]tags as follows: \infty \int[/tex]
 
Last edited:
Yes, it's a french name. But that doesn't really help me a lot :-p
 
OK, thanks!
 
I'm not sure, I think its only 0/0, as it comes from the Taylor expansion about the point that x approaches, ie.

[tex]\lim_{x\rightarrow a}\frac{f(x)}{g(x)} = \lim_{x\rightarrow a}\frac{f(a) + f'(x)(x-a) + ...}{g(a) + g'(x)(x-a) + ...} = \lim_{x\rightarrow a}\frac{f'(x)}{g'(x)}[/tex]

With f(a)=g(a)=0

Something like that anyway.
 
No you can use l'hospital's Rule for indeterminate forms, not just 0/0.
 

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