- #1
anderma8
- 35
- 0
L'Hopital's Rule - I'm loosing my hair!
Ok, I have the following:
Lim x->0 sqrt(4-x^2) -2 /x
After I change the equation to remove the radicle, I get:
Lim x->0 ((4-x^2)^1/2 - 2)/x
but when I apply the rule the, I'm loosing it I thought I should get:
1/2 ((4-x^2)^-1/2 times 2x)/1
What am I doing wrong?
Ok, I have the following:
Lim x->0 sqrt(4-x^2) -2 /x
After I change the equation to remove the radicle, I get:
Lim x->0 ((4-x^2)^1/2 - 2)/x
but when I apply the rule the, I'm loosing it I thought I should get:
1/2 ((4-x^2)^-1/2 times 2x)/1
What am I doing wrong?