L'Hospital Rule: Solving with (a) or (b)?

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SUMMARY

The discussion centers on the application of L'Hôpital's Rule in solving limits, specifically comparing two methods: (a) directly applying L'Hôpital's Rule to the numerator and (b) using logarithmic reduction before applying L'Hôpital's Rule. The correct approach is (a), as the derivative in method (b) was incorrectly calculated due to a failure to apply the chain rule properly. The correct derivative of the logarithmic expression is derived as \(\frac{1}{x+1}\), confirming that both methods yield the same result when applied correctly.

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jack1234
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[SOLVED] About l'hopital rule

I have two solutions for a question about limit
http://tinyurl.com/2pknkb

May I know is (a) correct, or (b)?
What is the reason for the other to be wrong?

Note:
(a) just directly applies l'hopital rule to numerator
(b) is to reduce the numerator using logarithm formula before using l'hopital rule
 
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You didn't calculate the derivative correctly for (b). You need to apply the chain rule. If you had computed it correctly you would have arrived at the same answer as for (a).

[tex]\frac d{dx}(\ln(x+1)-\ln(2)) = \frac d {dx} \ln\left(\frac{x+1} 2\right) = \frac 2 {x+1} \; \frac d {dx}\frac {x+1} 2 = \frac 2 {x+1} \, \frac 1 2 = \frac 1 {x+1}[/tex]
 
I see, thank you very much!
 

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