Lifting a canister with a pulley

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The discussion centers on calculating the force required to lift a 25 kg canister using a pulley system. The correct force, F, is derived from the equation F = mg/d, where m is the mass (25 kg) and g is the acceleration due to gravity (9.81 m/s²). The user initially miscalculated the force by not considering the 2:1 mechanical advantage provided by the pulley system, which means the force exerted should be halved to maintain a constant speed while lifting the canister.

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In the figure, a cord runs around two massless, frictionless pulleys; a canister with mass m = 25 kg hangs from one pulley; and you exert a force F on the free end of the cord. What must be the magnitude of F if you are to lift the canister at a constant speed?

Here i know that the answer is mg*d. So 25*9.81*0.066m but i am not getting the answer. as i have in the book. in the previous question was To lift the canister by 3.3 cm i had to lift it by 6.6 cm so i don't what i am doing that i s wrong. Thanks for the help
 
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There is no figure associated with your post, but from the last thing you said, it sounds like the pulley arrangement gives you a 2:1 force advantage. Did you take that into account in your calculation for the first question?
 

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