Lifting/breaking an object with circular motion

AI Thread Summary
In a centripetal force experiment involving a washer and a stopper, the upward movement of the washer is attributed to increased tension in the rope as the stopper is whirled faster. This tension exceeds the weight of the washer, allowing it to rise. Similarly, when a nut is attached to a rod and whirled, the increasing speed generates a force that eventually leads to the nut breaking due to excessive tension. The discussion emphasizes that tension in the rope increases with speed, which can lead to breaking if it surpasses the material's strength. Understanding these forces is crucial for analyzing the dynamics of circular motion and the effects of tension.
great_scott
Messages
9
Reaction score
0
i have two questions i think are asking almost the same thing.

1) in this typical centripetal force experiment; there are a stopper mass attacthed to one end of a rope and a washer attached to the other end of the rope. as the washer hangs straight down, i start whirling the stopper. after a point, the faster i whirl it, the more the washer goes up. the question is what is the force that pulls the washer upwards? i assume the tension must always be equal to the centripetal force that is created by the weight of the washer so it shouldn't be enough to beat the weight of the washer to lift it.

2)there is a nut or something breakable on an end of a rod and as you whirl the rod vertically keeping the nut in a circular motion. as you do it faster and faster you observe the nut breaks or at least gets damage soon or later. what is the force that breaks the nut?

thanks.
 
Physics news on Phys.org
great_scott said:
the question is what is the force that pulls the washer upwards?
The string tension.
i assume the tension must always be equal to the centripetal force that is created by the weight of the washer so it shouldn't be enough to beat the weight of the washer to lift it.
Don't assume that the tension just equals the weight of the washer. By spinning the stopper faster, you create more tension, which raises the washer.
2)there is a nut or something breakable on an end of a rod and as you whirl the rod vertically keeping the nut in a circular motion. as you do it faster and faster you observe the nut breaks or at least gets damage soon or later. what is the force that breaks the nut?
The faster you whirl the rod, the greater force it must exert on whatever is attached to it. Eventually, something breaks.
 
how do i creat more tension with no additional force? and obviously as the washer goes up it gains some more potential energy so there has got to be a net force that does some work against gravity by raising the washer?
i can actually put it that way what force makes the rope break when i whirl an object attachted to the rope fast enough? let's say vertically and above my head.
 
great_scott said:
how do i creat more tension with no additional force? and obviously as the washer goes up it gains some more potential energy so there has got to be a net force that does some work against gravity by raising the washer?
Tell me how you get the stopper to go faster.
i can actually put it that way what force makes the rope break when i whirl an object attachted to the rope fast enough? let's say vertically and above my head.
When the string tension gets too high, the string breaks. You are pulling on the string with a greater force as you twirl it faster.
 
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
This has been discussed many times on PF, and will likely come up again, so the video might come handy. Previous threads: https://www.physicsforums.com/threads/is-a-treadmill-incline-just-a-marketing-gimmick.937725/ https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/ https://www.physicsforums.com/threads/how-do-we-calculate-the-energy-we-used-to-do-something.1052162/
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top