Light from Train Scenario: Student Question Explained

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SUMMARY

The discussion centers on the physics of velocity addition, specifically in the context of a train moving at 200 km/h and a bullet fired at 800 km/h. While simple addition of velocities suggests the bullet would travel at 1000 km/h relative to the ground, this is inaccurate at relativistic speeds. The correct approach involves the relativistic velocity addition formula: v' = (v + u) / (1 + uv/c²). The conversation also touches on the implications of shining a torch in the direction of the train, emphasizing that light does not simply add speed in this scenario.

PREREQUISITES
  • Understanding of basic physics concepts, particularly velocity and motion.
  • Familiarity with the speed of light and its significance in physics.
  • Knowledge of relativistic physics, specifically the concept of relativistic velocity addition.
  • Basic mathematical skills to manipulate equations involving speed and velocity.
NEXT STEPS
  • Research "relativistic velocity addition" to understand its implications in high-speed scenarios.
  • Explore the concept of "invariance of the speed of light" in different reference frames.
  • Conduct experiments using the relativistic velocity addition formula with various speeds.
  • Study the effects of relativistic speeds on time dilation and length contraction.
USEFUL FOR

Students of physics, educators teaching relativity, and anyone interested in the principles of motion and light in the context of special relativity.

Fred Choi
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I am a student, and a few days ago in physics class we were discussing about the 'bullet fired from a train scenario', where e.g. if a train is heading towards a certain direction at 200 km/h and a bullet is fired at 800 km/h, the bullet would travel at 1000 km/h relative to the ground. However, one my friends asked an interesting question that even my teacher struggled to answer:
What if a torch was shone in the same direction as the train was travelling? Would the wave travel at the speed of light plus the speed of the train? But after all, nothing travels faster than the speed of light. Please help me with this! Thanks
 
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The simple addition of velocities is only valid for velocities much smaller than the speed of light. 800 km/h and 1000 km/h are both much smaller than the speed of light and therefore it is a (very) good approximation to assume simple addition of velocities. When you deal with velocities close to the speed of light, you need to use relativistic addition of velocities, which is given by
$$
v' = \frac{v+u}{1+\frac{uv}{c^2}}.
$$

Suggested exercise: Try this out for v = 800 km/h and u = 200 km/h and see how much the result differs from 1000 km/h.
 
Fred Choi said:
I am a student, and a few days ago in physics class we were discussing about the 'bullet fired from a train scenario', where e.g. if a train is heading towards a certain direction at 200 km/h and a bullet is fired at 800 km/h, the bullet would travel at 1000 km/h relative to the ground.
It doesn't move at exactly 1000 km/hr relative to the ground. If ##u## is the speed of the train and ##v## is the speed of the bullet, the correct formula is not ##u+v##, it is ##(u+v)/(1+uv/c^2)## where ##c## is the speed of light. The difference is completely unnoticeable at the sorts of speeds you're taking about, but it is there. (Google for "relativistic velocity addition" for more information).

However, one my friends asked an interesting question that even my teacher struggled to answer:
What if a torch was shone in the same direction as the train was travelling? Would the wave travel at the speed of light plus the speed of the train? But after all, nothing travels faster than the speed of light. Please help me with this! Thanks
Try setting ##v=c## in the formula above, see what you get for the speed of the wavefront... It's is actually kinda fun to see how it comes out.

[edit: Curses! Beaten by Orodruin again! In need a faster internet connectioon! :smile:]
 

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