Light from Train Scenario: Student Question Explained

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
Fred Choi
Messages
1
Reaction score
0
I am a student, and a few days ago in physics class we were discussing about the 'bullet fired from a train scenario', where e.g. if a train is heading towards a certain direction at 200 km/h and a bullet is fired at 800 km/h, the bullet would travel at 1000 km/h relative to the ground. However, one my friends asked an interesting question that even my teacher struggled to answer:
What if a torch was shone in the same direction as the train was travelling? Would the wave travel at the speed of light plus the speed of the train? But after all, nothing travels faster than the speed of light. Please help me with this! Thanks
 
Physics news on Phys.org
The simple addition of velocities is only valid for velocities much smaller than the speed of light. 800 km/h and 1000 km/h are both much smaller than the speed of light and therefore it is a (very) good approximation to assume simple addition of velocities. When you deal with velocities close to the speed of light, you need to use relativistic addition of velocities, which is given by
$$
v' = \frac{v+u}{1+\frac{uv}{c^2}}.
$$

Suggested exercise: Try this out for v = 800 km/h and u = 200 km/h and see how much the result differs from 1000 km/h.
 
Fred Choi said:
I am a student, and a few days ago in physics class we were discussing about the 'bullet fired from a train scenario', where e.g. if a train is heading towards a certain direction at 200 km/h and a bullet is fired at 800 km/h, the bullet would travel at 1000 km/h relative to the ground.
It doesn't move at exactly 1000 km/hr relative to the ground. If ##u## is the speed of the train and ##v## is the speed of the bullet, the correct formula is not ##u+v##, it is ##(u+v)/(1+uv/c^2)## where ##c## is the speed of light. The difference is completely unnoticeable at the sorts of speeds you're taking about, but it is there. (Google for "relativistic velocity addition" for more information).

However, one my friends asked an interesting question that even my teacher struggled to answer:
What if a torch was shone in the same direction as the train was travelling? Would the wave travel at the speed of light plus the speed of the train? But after all, nothing travels faster than the speed of light. Please help me with this! Thanks
Try setting ##v=c## in the formula above, see what you get for the speed of the wavefront... It's is actually kinda fun to see how it comes out.

[edit: Curses! Beaten by Orodruin again! In need a faster internet connectioon! :smile:]