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Light incident on a grating for spectroscopy

  1. Nov 13, 2009 #1
    1. The problem statement, all variables and given/known data
    if light incident on a grating makes an angle phi with the normal of the grating, show that the equation m(lambda)=d(sin(theta)) becomes m(lambda)=d[sin(theta-phi)+sin(phi)]

    2. Relevant equations

    m(lambda)=d(sin(theta)) d=spacing of slits, theta=angle displaced from normal of the grating

    3. The attempt at a solution
    I've been working on trying to get a solution to this equation for quite some time now, and the only thing that makes sense is the equation m(lambda)=d*sin(theta-phi). don't know where +sin(phi) comes from.
  2. jcsd
  3. Nov 13, 2009 #2


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    I don't get either of those answers!
    Maybe we can put our heads together and sort out our differences!
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