Light rays reflected off vertical mirror (law of reflection)

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SUMMARY

The discussion focuses on solving a geometry problem involving the law of reflection with a vertical mirror positioned at the origin. The coordinates of points A (11.4, 15.9) and B (15.9, 4.7) are provided, and participants emphasize the relationship between the incident and reflected angles. The key to solving the problem lies in understanding the slopes of the lines connecting points A, C (the point of reflection), and B. The correct equation to find the height of point C is established as 15.9 - c / 11.4 = -((c - 4.7) / 15.9), with a correction made regarding the sign in the equation.

PREREQUISITES
  • Understanding of the law of reflection in optics
  • Basic knowledge of coordinate geometry
  • Familiarity with trigonometric functions and their applications
  • Ability to calculate slopes and interpret linear equations
NEXT STEPS
  • Study the properties of angles and slopes in coordinate geometry
  • Learn about the law of reflection and its applications in optics
  • Practice solving problems involving reflections and angles using trigonometry
  • Explore graphical methods for visualizing geometric relationships
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Students studying geometry, physics enthusiasts, and anyone interested in understanding the principles of light reflection and its mathematical applications.

PhysicsMan999
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Homework Statement



  1. A vertical mirror is placed at the origin. A ray of light coming from A is reflected by the mirror so that it passes through B. How far from the bottom does the ray hit the mirror? The coordinates are A = (11.4, 15.9) and B = (15.9, 4.7), in centimetres.

Homework Equations


incident angle=reflected angle
tan@=tan@=h/x

The Attempt at a Solution


So, I drew my diagram, and I know that the rule of reflection means that the incident angle from A will be equal to the reflective angle to B. I'm just trying to use trig to solve it but I'm having no luck. I drew a triangle connecting A an B, with it having a hypotenuse of 12.07, solved for its other angles, and cannot seem to relate it to the mirror height.
 
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Here's a hint. Call point C where the light ray hits the mirror. Imagine lines (rays) from A to C and from C to B. How are those lines related?
 
They're both arriving at/leaving C at the same angle right?
 
PhysicsMan999 said:
They're both arriving at/leaving C at the same angle right?
Good. What other property of a line expresses the angle it makes?
 
Can you elaborate on that a bit? I'm not really sure what you mean..
 
Consider the slope of those lines.
 
They would be the same I believe.
 
PhysicsMan999 said:
They would be the same I believe.
Draw yourself a picture and see. How is slope defined?
 
rise/run. the C-B slope would just be the negative of A-B's slope. I've had the picture for awhile I just can't figure out how to get the right info to solve it
 
  • #10
PhysicsMan999 said:
rise/run. the C-B slope would just be the negative of A-B's slope.
Exactly! You'll need to express that mathematically.

PhysicsMan999 said:
I've had the picture for awhile I just can't figure out how to get the right info to solve it
You are given the coordinates of A and B. Set up an equation, and you can solve for the unknown height of C.
 
  • #11
so the equation i set up was:
15.9-c/11.4= -((c-4.7)/15.9)
This is giving me an answer that makes no sense (68.08cm)
 
  • #12
PhysicsMan999 said:
so the equation i set up was:
15.9-c/11.4= -((c-4.7)/15.9)
Almost. You messed up the sign.
 
  • #13
Ahhh, I see now. Thank you very much! I was trying to solve it a completely different way haha no wonder I couldn't figure it out
 

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