Light Speed Consistency: Puzzling Questions

  • Context: Graduate 
  • Thread starter Thread starter squeeky100
  • Start date Start date
  • Tags Tags
    Lightspeed
Click For Summary

Discussion Overview

The discussion centers around the concept of the constancy of light speed, particularly in the context of a space vehicle moving at near light speed and emitting a light ray. Participants explore the implications of this scenario from different frames of reference, questioning how the speed of light is perceived by observers in various situations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions whether a light ray emitted from a vehicle moving at near light speed would move away at speed c or at a separation speed of c - ~c, while also considering the perspective of different observers.
  • Another participant suggests that since the Earth is also moving at near light speed relative to distant galaxies, the measurement of light speed should remain consistent according to Maxwell's equations, raising the question of why other spaceships would measure it differently.
  • A participant clarifies that from an outsider's frame of reference, the separation speed would be c - ~c, while from the ship's perspective, it would be c, emphasizing the consistency of these observations due to differing time flows for each observer.
  • One participant reiterates the puzzling nature of light speed constancy and introduces a mathematical approach to velocity addition, illustrating that light speed remains c for all observers, with differences only in the observed wavelength.

Areas of Agreement / Disagreement

Participants express differing views on how light speed is perceived from various frames of reference, indicating that multiple competing perspectives remain without a consensus on the implications of these observations.

Contextual Notes

Discussions involve assumptions about the nature of light speed and the effects of relativistic physics, with unresolved questions regarding the implications of these assumptions on measurements and observations.

squeeky100
Messages
4
Reaction score
0
The concept of light speed being constant is puzzling to me. For instance, if a space vehicle is moving through space at near light speed (~c) and emits a light ray at speed c, does the light ray move away from the vehicle at speed c or is the separation speed (c - ~c) ? (Ignore constaints that would prevent the vehicle from achieving near light speed) Also, what would an observer see - maybe, the light ray and vehicle moving at almost the same speed c and ~c ?
 
Science news on Phys.org
Consider that the Earth is a space vessel traveling at near light speed with respect to distant galaxies. We measure c to be exactly that which is predicted by Maxwells equations. Why would any other spaceship measure it any differently?
 
squeeky100 said:
For instance, if a space vehicle is moving through space at near light speed (~c) and emits a light ray at speed c, does the light ray move away from the vehicle at speed c or is the separation speed (c - ~c) ?

From what frame of reference? From the point of view of an outsider, the separation would be c - ~c, while from the point of view of the ship, the separation would be c.

Note that these two cases are completely consistent with each other by virtue of the fact that time flows differently for each observer.

Claude.
 
squeeky100 said:
The concept of light speed being constant is puzzling to me. For instance, if a space vehicle is moving through space at near light speed (~c) and emits a light ray at speed c, does the light ray move away from the vehicle at speed c or is the separation speed (c - ~c) ? (Ignore constaints that would prevent the vehicle from achieving near light speed) Also, what would an observer see - maybe, the light ray and vehicle moving at almost the same speed c and ~c ?

Velocities do not add in the "usual" way …

(i'm putting c = 1, to make the equations prettier :wink:)

adding velocity u to velocity v (in the same direction) gives w = (u + v)/(1 + uv).

Put u = 1 (ie, light-speed), then w = (1 + v)/(1 + v) = 1 also. :biggrin:

So a speed of 1 is seen as 1 by every observer, and the only visual difference is the colour (wavelength) of the light.​
 

Similar threads

  • · Replies 26 ·
Replies
26
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
3
Views
2K
  • · Replies 34 ·
2
Replies
34
Views
4K
  • · Replies 5 ·
Replies
5
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
697
  • · Replies 40 ·
2
Replies
40
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 9 ·
Replies
9
Views
1K