Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Lim as x goes to a of sqrtx = sqrta

  1. Sep 20, 2009 #1
    this is a theorem that has a proof. in the proof they use a constant c so that epsilon is not in terms of x when you go to prove it. can someone explain this proof and also how and why you get/use a constant c to prove this theorm?
     
  2. jcsd
  3. Sep 20, 2009 #2
    I would have to see this proof to explain it.
    With the typical epsilon/delta proof of a limit, to prove that lim x->a f(x) = L you need to prove that for EVERY epsilon, a delta exists such that if a-delta < x < a+delta, then |f(x)-L| < epsilon.
    epsilon is arbtrary and not in terms of x or anything else, and delta will be a funtion of epsilon that you will have to choose to make |f(x)-L| small enough.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Lim as x goes to a of sqrtx = sqrta
  1. Proof lim (x+1)^(1/x)=e (Replies: 20)

  2. Lim (x/x+1)^x (Replies: 5)

  3. Lim x -> 0 problem (Replies: 2)

Loading...