Limit of (3x^3+2)/sqrt(x^4-2) as x→-∞

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SUMMARY

The limit of the expression (3x^3 + 2) / sqrt(x^4 - 2) as x approaches negative infinity is definitively minus infinity. This conclusion arises from the observation that for large negative values of x, the numerator (3x^3 + 2) remains negative while the denominator (sqrt(x^4 - 2)) remains positive, leading to a negative limit. The initial confusion regarding the limit being plus infinity is clarified through this analysis.

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Homework Statement


limit of (3x^3+2)/ sqrt(x^4-2) as x approaches to minus infinity


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The Attempt at a Solution


I tried to solve and I came up with limit of (3x^3+2)/ sqrt(x^4-2) as x approaches to minus infinity is plus infinity but when I checked the answer key, it is minus infinity can someone please tell me?
 
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Hi chemic_23! :smile:
chemic_23 said:
I tried to solve and I came up with limit of (3x^3+2)/ sqrt(x^4-2) as x approaches to minus infinity is plus infinity but when I checked the answer key, it is minus infinity can someone please tell me?

Easy-peasy :-p

for large negative x, the top is always negative, while the bottom is always positive …

so the limit has to be negative. :smile:
 

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