Limit of a sequence does not goes to zero

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SUMMARY

The proof demonstrates that if a sequence has an ever-increasing term, then its limit cannot be zero. Specifically, it establishes that if the limit of the sequence, denoted as ##\lim_{n \to \infty} a_n##, is assumed to be zero, it leads to a contradiction with the condition ##|a_n| < |a_{n+1}|##. The argument shows that for sufficiently large n, the terms of the sequence cannot satisfy both conditions simultaneously, confirming that the limit must be non-zero.

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Seydlitz
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Homework Statement


Could you guys please verify this proof of mine? I want to show that a limit with particular property does not go to 0. It is part of the proof that when a sequence have an ever increasing term then the limit of the sequence is not 0.

The Attempt at a Solution



The ##\lim_{n \to \infty} a_n \neq 0## if ##|a_n|<|a_{n+1}|##

Suppose ##\lim_{n \to \infty} a_n = 0##, then there exist ##n>0##, such that ##|a_N| < \epsilon## when ##N>n##. Taking an arbitrary ##a_n## as ##\epsilon##, we can get ##|a_N| < |a_n|.## Because it also true that ##N=n+1>n##, we get ##|a_n|>|a_{n+1}|##. A contradiction.

Hence it is not possible for the limit to be 0.

Thank You
 
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Seydlitz said:

Homework Statement


Could you guys please verify this proof of mine? I want to show that a limit with particular property does not go to 0. It is part of the proof that when a sequence have an ever increasing term then the limit of the sequence is not 0.

The Attempt at a Solution



The ##\lim_{n \to \infty} a_n \neq 0## if ##|a_n|<|a_{n+1}|##

Suppose ##\lim_{n \to \infty} a_n = 0##, then there exist ##n>0##, such that ##|a_N| < \epsilon## when ##N>n##. Taking an arbitrary ##a_n## as ##\epsilon##, we can get ##|a_N| < |a_n|.## Because it also true that ##N=n+1>n##, we get ##|a_n|>|a_{n+1}|##. A contradiction.

Hence it is not possible for the limit to be 0.

Thank You

That looks just fine to me.
 
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Ok thanks for your verification Dick! I'm quite happy to discover this by myself.
 

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