Limit of sec(x) as x goes to pi/2, does the limit exist?

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SUMMARY

The limit of sec(x) as x approaches π/2 from the left does not exist. This is due to the fact that sec(x) is defined as 1/cos(x), and the value of cos(π/2) is 0. As x approaches π/2, cos(x) approaches 0, causing sec(x) to approach infinity. Therefore, the limit diverges and is considered undefined.

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Homework Statement



lim sec(x)
x-> pi/2 from the left

Homework Equations





The Attempt at a Solution


I wasn't quite sure where to start. I know sec is 1/cos. Does the limit not exist?
 
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What's the value of cos(pi/2)?
 

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