- #1
kitle545
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Homework Statement
lim sec(x)
x-> pi/2 from the left
Homework Equations
The Attempt at a Solution
I wasn't quite sure where to start. I know sec is 1/cos. Does the limit not exist?
A limit is a fundamental concept in calculus that describes the behavior of a function as its input approaches a certain value or point. It represents the value that a function approaches as its input gets closer and closer to a specific value, without actually reaching that value.
The limit of sec(x) as x approaches pi/2 is undefined, or does not exist. This is because the secant function is undefined at pi/2, as the cosine of pi/2 is equal to 0, making the secant function approach infinity.
A limit exists if the left-hand limit and the right-hand limit are equal. This means that as x approaches the specific value, the function approaches the same value from both the left and the right side. If the left-hand and right-hand limits are not equal, then the limit does not exist.
No, direct substitution cannot be used to evaluate the limit of sec(x) as x approaches pi/2. This is because direct substitution can only be used when the function is defined at the specific value, but sec(x) is undefined at pi/2.
The limit of sec(x) as x approaches pi/2 is important because it represents the behavior of the secant function near this critical value. It also helps to understand the behavior of other trigonometric functions, such as cosine and tangent, as they are related to the secant function.