Limit of Series: Proving lim n→∞ ∑e^-n n^k/k! = 1/2

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Homework Help Overview

The discussion revolves around proving the limit of a series involving the exponential function and factorials, specifically lim n→∞ ∑(e^-n n^k/k!) = 1/2. The subject area includes series convergence and properties of exponential functions.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the handling of the series and the implications of taking the limit as n approaches infinity. There is an attempt to relate the series to the Taylor expansion of e^n, and questions arise about the interpretation of variables in the limit process. Some participants suggest using integral approximations and mention the relevance of Gamma functions.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations and approaches to the problem. Some guidance has been offered regarding the handling of limits and series, but there is no explicit consensus on the correct method or outcome yet.

Contextual Notes

One participant notes a lack of familiarity with the Central Limit Theorem and Poisson distributions, which may be relevant to the problem at hand. There is also mention of the context of applying for a Master's program, indicating the problem's significance to the participant's academic pursuits.

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Homework Statement



prove that lim n→∞ of [itex]\sum[/itex][itex]^{n}_{k=0}[/itex] e[itex]^{-n}[/itex] n[itex]^{k}[/itex] / k! = 1/2

The Attempt at a Solution



I seem to be mishandling the series. After taking n→∞, the sum of (n^k)/k! is just the taylor series expansion of e^n. Then I should get e^(-n)*e^n = 1.

Where am I going wrong??
 
Last edited:
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You're messing up your variables.

You say "After taking the limit [itex]n\rightarrow +\infty[/itex]". But you seem to interpret that only has "making the sum infinite".

The expressions [itex]e^{-n}[/itex] and [itex]n^k[/itex] also depend on n. So if you take the limit as [itex]n\rightarrow +\infty[/itex], then those things don't stay the same.

Allow me to totally butcher mathematics for a moment, but it's to make things clear. If you take the limit [itex]n\rightarrow +\infty[/itex] of your expression then you don't end up with

[tex]e^{-n}\sum_{k=0}^{+\infty}\frac{n^k}{k!}[/tex]

Rather, you would end up with (please forgive me)

[tex]e^{-\infty}\sum_{k=0}^{+\infty}\frac{\infty^k}{k!}[/tex]

The above of course makes no sense. But I think it makes the situation clear.
 
Prove that what? That the series converges?
 
Sorry, prove the limit = 1/2 (could have sworn I had written it).

Micromass, thanks. I would be lying if I said I didn't suspect that was the problem, it still kind of makes me uneasy.

Anyways now I am trying to replace the sum by an integral (Euleur-Maclaurin), and I get:

[itex]\sum[/itex][itex]^{n}_{k=0}[/itex] e[itex]^{-n}[/itex][itex]\frac{n^k}{k!}[/itex] = 1/2 + [itex]\frac{e^{-n}}{2}[/itex][itex]\frac{n^n}{(n!)}[/itex] + [itex]\int[/itex][itex]^{n}_{0}[/itex] e[itex]^{-n}[/itex][itex]\frac{n^k}{k!}[/itex]dk

so I have hopes because the 1/2 is there to stay, the 2nd term probably goes to zero after taking the limit, same with the integral except I don't know how to handle the factorial in the integral. Now I am reading on Gamma functions.. maybe that will help.
 
Last edited:
It may sound like a strange question, but do you know the Central Limit Theorem and Poisson distributions?
 
micromass said:
It may sound like a strange question, but do you know the Central Limit Theorem and Poisson distributions?

No, I haven't learned them.. although googling Poission distributions.. it seems it is related to my problem.

In applying for a Masters in Fluid Dynamics (Math) after getting a Physics Undergrad, one of my potential supervisors gave me a set of problems to 'check me out'. I killed most of them without too much sweat and tears, but this one really I'm having a hard time with.

Anyways,I will read about Poisson distributions and Central Limit Theorem.
 

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