how would you do:(adsbygoogle = window.adsbygoogle || []).push({});

lim x->3+ of abs(x+3) / x^2 - 9

because if you take the difference of squares of the bottom

and divide x+3 / x+3 for the positive abs case

you are left with 1/(x-3) with x approaching 3

making the denominater 0

I have since realized that the question was asking for -3+, and was able to solve it

but if it was asking for +3+ how could I go about solving it?

Thanks

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# Homework Help: Limit Problem Difference of Squares

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