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Limits equation

  1. Jul 31, 2013 #1
    so i was working on this equation , and in the end i came to
    Lim H>0 2-h+2xh
    so now i am supposed to treat H as 0
    so shouldnt it be 2-(0)+2x(0) = 2 ?
    i know the answer is 2-2x , as if we just removed the H , but isn't multiplying anything be zero make it a zero itself ? * 2x*0 = 0 ?
  2. jcsd
  3. Jul 31, 2013 #2


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    Hey B4ssHunter.

    Is there meant to be a h in the denominator? Is this is some sort of differentiation problem via first principles?
  4. Jul 31, 2013 #3


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    Gold Member

    how can there be an h in the denominator. that would make it undefined
  5. Jul 31, 2013 #4


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    IF lim(h->0) 2- h+ 2xh is, in fact, correct, then the limit is 2, not 2- 2x.

    So if you you say "I know the answer is 2- 2x", then 2- h+ 2xh must be incorrect. Please tell us what the entire problem is.
  6. Jul 31, 2013 #5
    oh i apologize , i made a sign mistake .. i am really really sorry :S
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